Ramón Aguilar - Mexican military and agrarian. Article “Ramón Aguilar Ceja” in Spanish Wikipedia has 31.2 points for quality (as of July 1, 2026). The article contains 22 references and 7 sections.
In June 2026 the article “Ramón Aguilar Ceja” was edited by 1 authors in Spanish Wikipedia and written by 1 authors in all languages.
Since the creation of article “Ramón Aguilar Ceja”, its content was written by 12 registered users of Spanish Wikipedia and edited by 12 registered Wikipedia users in all languages.
The article is cited 1 times in Spanish Wikipedia and cited 1 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2026 (including revision history and pageviews for previous years).
| Best Rank | Spanish: #426541 12.2022 |
Global: #4037681 12.2022 |
| Best Rank | Spanish: #2117 12.2022 |
Global: #88484 12.2022 |
On 16 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 98th Academy Awards, Michael B. Jordan, Sinners, Jessie Buckley, Paul Thomas Anderson, Sean Penn, One Battle After Another, Amy Madigan, Hamnet, Timothée Chalamet.
In Spanish Wikipedia the most popular articles on that day were: 98.ª edición de los Premios Óscar, Una batalla tras otra, Michael B. Jordan, Marcelo Araujo, Paul Thomas Anderson, Amy Madigan, Jessie Buckley, Sean Penn, Sinners, Hamnet (película).
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 50 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2026. When calculating current popularity and AI of articles data from June 2026 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2026... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(10.4+13.58+0+31.82+100)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
